x^2+102x-2160=0

Solution for x^2+102x-2160=0 equation:

x^2+102x-2160=0

a = 1; b = 102; c = -2160;
Δ = b2-4ac
Δ = 1022-4·1·(-2160)
Δ = 19044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19044}=138$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(102)-138}{2*1}=\frac{-240}{2}
=-120
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(102)+138}{2*1}=\frac{36}{2}
=18
$